d(uv) = u dv + v du
where:
v = [exp(c2/( T) -1)]-1
We need to take the derivative of this term. There are two possibilities:
Case 1 here the power, t, equals -1. Immediately we have dv =
-1 [exp(c2/( T) -1)]-2 dZ. Now we must find the
derivative of the exponential term. The devivative of an exponential
is simply the exponential term itself multiplied by the derivative of the
exponent. In this case, since we are taking the derivative with respect to
wavelength, , the derivative of the exponent is
dv = [c2/(2 T)] [exp(c2 /T)/(exp(c2 /T) - 1)2].
Case 2: the derivative of 1, a constant, is 0, so the first term in the numerator drops out. For the second term, we must again know what the derivative of exp(c2/( T) - 1) is. Using our result above, combining these terms (and noticing that they will be multiplied by -1), we again get the expression below.
dv = [c2/(2 T)] [exp(c2 /T)/(exp(c2 /T) - 1)2].
Not surprisingly, they are identical.